what mass of sodium chloride contains 4.59*10^24
4.59 x 10^24 what? Choose any number and you will be right.
To determine the mass of sodium chloride containing 4.59*10^24 formula units, we need to follow a step-by-step process. Here's how you can calculate it:
Step 1: Determine the formula for sodium chloride (NaCl).
Sodium chloride is composed of one sodium ion (Na+) and one chloride ion (Cl-).
Step 2: Find the molar mass of sodium chloride.
The molar mass is the mass of one mole of a substance. The molar mass of NaCl can be calculated by adding the atomic masses of sodium (Na) and chlorine (Cl), which can be found on the periodic table.
The atomic mass of sodium (Na) is approximately 22.99 g/mol, and the atomic mass of chlorine (Cl) is approximately 35.45 g/mol.
So, the molar mass of NaCl is 22.99 g/mol (for Na) + 35.45 g/mol (for Cl) = 58.44 g/mol.
Step 3: Convert formula units to moles.
We are given 4.59*10^24 formula units of NaCl. To determine the number of moles in this quantity, we need to use Avogadro's number, which is approximately 6.022 x 10^23 formula units per mole.
So, the number of moles in 4.59*10^24 formula units can be calculated as:
moles = (4.59*10^24 formula units) / (6.022 x 10^23 formula units/mol)
Step 4: Calculate the mass of sodium chloride.
To find the mass of NaCl, we multiply the number of moles calculated in Step 3 by the molar mass of NaCl calculated in Step 2.
mass = moles * molar mass
Performing the calculation, the mass of sodium chloride containing 4.59*10^24 formula units can be found using the above formula.