# check!

here is the question:
log5(x-4)= log7x solve for x.

These are just base 10 logs.
log100 = 2
This equation has the same format as log 40 = log (2x20)

Since both sides have log base 10, you divide by log base 10 and end up with 5(x-4) = 7x, so 5x -20 =7x x=-10

One doesn't exactly "divide by base 10".

log5(x-4)= log7x solve for x.
take each side as exponents to the base 10, or
10^(log5(x-4))= 10^(log7x)
then
5(x-4) = 7x
and x= 10
check...
log (5(-14)= log -70
log (-70)=log(-70) and it checks

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