A particle's constant acceleration is south at 2.4 m/s2. At t = 0, its velocity is 43.4 m/s east. What is its velocity at t = 8.0 s?
What is the magnitude and direction?
The east (x) component of velocity will stay the same. The south (y) velocity component is -2.4 t
Use the Vx and Vy compnents at 8.0 s to get the magnitude and direction of velocity. I assume you know how to do that.