the width of a rectangle is fixed at 30cm. What lengths will make the perimetear greater than 88cm
The width is 30 cm and there are two sides at 30 cm. Those two sides = 60 cm.
Call the length X and there are two of them so 60 + 2X = 88 for the perimeter.
Solve for X. I get 29 cm but you should verify that. Therefore anything longer than 29 cm for the length will have a perimeter greater than 88 cm. Check my work.
30+30+2x>88; 30+30=60; 60-(30+30)+2x>88; 2x/2>28/2; x>14. > is greated than
ii need roux
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To find the lengths that will make the perimeter of the rectangle greater than 88 cm, we need to understand the formula for calculating the perimeter of a rectangle.
The formula for the perimeter of a rectangle is: P = 2(length + width).
Given that the width is fixed at 30 cm, we can substitute it into the formula: P = 2(length + 30).
Now we can solve for the lengths that will result in a perimeter greater than 88 cm.
1. Start by rearranging the formula:
P > 88
2(length + 30) > 88
2. Divide both sides of the inequality by 2:
length + 30 > 44
3. Subtract 30 from both sides of the inequality:
length > 14
Therefore, any length greater than 14 cm will make the perimeter greater than 88 cm.