Physics

An electrostastic force of 20.0 newtons is exerted on a charge of 8.00 x 10^/2 C at point P in an electric field. The magnitude of the electric field strength at P is

Given:
Fe = 20 B
q = 8.00 x 10^/2 C

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  1. Use F = Q * E

    Solve for E, in Newtons per Coulomb

    Fe = 50 N(ewtons), NOT 50 B
    I think you made a typing error

    I do not understand why you put an / in front of the exponent, 2, of the charge (Q)

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  2. Oh im really sorry, its 8.00 x 10^-2

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