Calculus

Find the surface area formed by revolving the graph of f(x)=81-x^2 on the interval [0,9] about the y-axis. (express the answer in terms of pie.)

  1. 👍 0
  2. 👎 0
  3. 👁 102
asked by Nancy

Respond to this Question

First Name

Your Response

Similar Questions

  1. Calculus AP Exam review explanation pls

    1)What is the area bounded by y = x^2 and y =3x? A)5 B)9/2 ***C)8 D)11.2 E)25 i believe it to be 8 but im not sure. 2)The region R is bounded by the x-axis, x = 2, and y = x^2. Which of these expressions represents the volume of

    asked by ReviewDay :( on March 3, 2017
  2. calculus

    Let R be the region in the first quadrant that is enclosed by the graph of y = tanx, the x-axis, and the line x = π/3 h. Find the area of R i. Find the volume of the solid formed by revolving R about the x-axis

    asked by Naseba on April 4, 2012
  3. Calculus Urgent

    graph y=cos(pi*x/2) and y=1-x^2 and use integration to find the area in between the curve. Okay, so when I graph these two I see that they like overlap during the [-1,1] x interval. But maybe there is still a small gap in between?

    asked by Bethany on March 27, 2016
  4. math-cal.

    find the volume of the solid formed by revolving the region bounded by the graph of y=2x^2+4x and y=0 about the y- axis ( express the answernin terms of pie)

    asked by Nancy on February 2, 2010
  5. calculus(Lab)

    Well, first graph the graph of f(x)=-1/10x^2 + 3 2. We are going to approximate the area between f and the x-axis from x = 0 to x = 4 using rectangles (the method of Riemann sums). This is not the entire area in the first

    asked by Yoona on January 25, 2012
  6. ap calc

    find the volume generated by revolving the area bounded by y=-x^3, y=0, and x=-2 about the line x=1. I know how to the solve the problem but am not sure how to get the interval. Please help.

    asked by anonymous on February 28, 2015
  7. Math

    Find the area of the surface generated by revolving the curve y = (x + 3)^1/2, 2 ≤ x ≤ 4 about the x-axis.

    asked by Alex on September 21, 2010
  8. Integral Calculus

    Find the area of the surface generated by revolving the given curve about the y-axis. 8xy^2=2y^6+1 , 1

    asked by Akitsuke on September 21, 2008
  9. Calculus

    (I know it looks like a lot but it's just 10 questions) (part 1 [It also explains my situation]: jiskha.com/questions/1788952/Hi-I-missed-school-due-to-illness-and-my-school-isnt-very-forgiving-so-I-would) (If your willing to do

    asked by George on March 18, 2019
  10. Integral calculus

    find the area of the surface generated by revolving about x-axis the upper half of the ellipse 4x^2 + 16y^2 = 64

    asked by Anonymous on May 29, 2016

More Similar Questions