physics

A drag racer, starting from rest, speeds up for 402 m with an acceleration of +24.0 m/s2. A parachute then opens, slowing the car down with an acceleration of -5.40 m/s2. How fast is the racer moving 3.75 102 m after the parachute opens?

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  1. Please post your attempt at solution.

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  2. x=1/2(vo+v)t

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  3. vo1 +1/2at2
    and vo2 +t i just don't know what numbers to put where

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