algebra

2x^2-8x-42 over 6x^2 divided by x^2-9 over x^2-3x

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  1. 2x^2-8x-42 over 6x^2 divided by x^2-9 over x^2-3x
    = (2x^2-8x-42)/(6x^2) รท [(x^2-9)/(x^2-3x)]
    = 2(x+3)(x-7/(6x^2)*x(x-3)/[(x+3)(x-3)]
    = (x-7)/(3x) after some lovely canceling.

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  2. (x-3)(x^2+x-7)

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