calculus

What quantity of 65 per cent acid solution must be mixed with a 25 percent solution to produce 384 mL of a 50 per cent solution?

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1. Let there be x mL of 65% solution and y mL of 25% solution.

x + y = 384

Amount of acid:
0.50*384 = 192 = 0.65 x + 0.25 y

768 = 2.6 x + y

Subtract the first equation from the third.

1.6 x = 384
x = 240 mL
y = 144 mL

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posted by drwls

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