college physics

The velocity of a particle is given by the relation v(t)=(-5.00 x 10⁷)t² = (3.00 x 1065)t. At time t=0, the particle is located at the origin. What is its location after 10 seconds?

  1. 👍
  2. 👎
  3. 👁

Respond to this Question

First Name

Your Response

Similar Questions

  1. physics

    Two forces, 1 = (3.85 − 2.85) N and 2 = (2.95 − 3.65) N, act on a particle of mass 2.10 kg that is initially at rest at coordinates (−2.30 m, −3.60 m). (a) What are the components of the particle's velocity at t = 11.8 s?

  2. math

    Consider a particle moving along the x-axis where x(t) is the position of the particle at time t, x' (t) is its velocity, and x'' (t) is its acceleration. x(t) = t3 − 12t2 + 21t − 7, 0 ≤ t ≤ 10 (a) Find the velocity and

  3. Physics

    The velocity graph of a particle moving along the x-axis is shown. The particle has zero velocity at t=0.00s and reaches a maximum velocity, vmax, after a total elapsed time, t total. If the initial position of the particle is x0

  4. Physics

    A 59 g particle is moving to the left at 29 m/s. How much net work must be done on the particle to cause it to move to the right at 38 m/s? .....i have tried two different ways and gotten the wrong answer. Kinetic Energy = 0.5 *

  1. physics

    A 2 kg particle has a velocity of (2i-3j) m/s and a 3kg particle has a velocity of (1i+6j)m/s.Find (a) the velocity of the center of mass(b) the total momentum of the system

  2. Calculus

    The displacement (in meters) of a particle moving in a straight line is given by s=2t^3 where is measured in seconds. Find the average velocity of the particle over the time interval [10,13]. the average velocity is 798 What is

  3. physics

    The position of a particle moving along an x axis is given by x = 15t2 - 2.0t3, where x is in meters and t is in seconds. (a) Determine the position, velocity, and acceleration of the particle at t = 3.0 s. x = m v = m/s a = m/s2

  4. Calculus

    The position of a particle moving on a horizontal line is given by s(t)=2t^3-15t^2+24t-5, where s is measured in feet and t in seconds. a: What is the initial position of the particle? b: What is the average velocity of the

  1. Calculus

    The Question: A particle moves along the X-axis so that at time t > or equal to 0 its position is given by x(t) = cos(√t). What is the velocity of the particle at the first instance the particle is at the origin? So far I was

  2. calculus

    5. A particle moves along the x-axis in such a way that its position at time t is given by x=3t^4-16t^3+24t^2 for -5 ≤ t ≤ 5. a. Determine the velocity and acceleration of the particle at time t. b. At what values of t is the

  3. Calculus

    The position of a particle moving along the x-axis at time t > 0 seconds is given by the function x(t) = e ^ t - 2t feet. a) Find the average velocity of the particel over the interval [1,3]. b) In what direction and how fast is

  4. physics

    A particle has an acceleration of +6.24 m/s2 for 0.300 s. At the end of this time the particle's velocity is +9.81 m/s. What was the particle's initial velocity?

You can view more similar questions or ask a new question.