find the slope of the line that contains (1,6) and 10,9) i thought the answer was -3/9 ( negative 3 over 9)
but i guess that is incorrect where did i go worng? any halp is greatly apreciated!
slope between the two points (1,6) and (10,9) is
(9-6)/(10-1)
= 3/9 = 1/3
thats what i thought but the choices for the answers are - 11/3, -3/11 or -5/3
thanks anyways!
Unless you made a mistake in typing, they are wrong!
To find the slope of a line, you need to use the formula:
slope = (change in y)/(change in x)
In this case, you have two points: (1, 6) and (10, 9).
To find the change in y, subtract the y-coordinates of the two points:
change in y = 9 - 6 = 3
To find the change in x, subtract the x-coordinates of the two points:
change in x = 10 - 1 = 9
Now you can calculate the slope:
slope = (change in y)/(change in x) = 3/9 = 1/3
Therefore, the slope of the line that contains the points (1, 6) and (10, 9) is 1/3, not -3/9.
You went wrong by incorrectly simplifying the fraction -3/9 to -1/3. The correct simplification would be -1/3, not -3/9. However, since the negative sign is typically placed in front of the numerator, the correct answer is 1/3.