# statistics

if i have
k = 36.86 +/- 4.78
and
v = 113 +/- 9.92
both using 95% confidence limits and no true values of k or v given
am i right in saying that accuracy cannot be determined
and that v is a more precise measurement

my question was to comment on what can be said about
the precision
the accuracy
and which is measured more precisely

thanks

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2. 👎
3. 👁
1. The confidence limits use the mean and the standard deviation (mean ± 1.96 SD for 95% confidence interval)). The less variable the confidence limits (lower SD), the more accurate/precise the estimate is.

I hope this helps.

1. 👍
2. 👎
2. i know that the standard deviation and confidence limits are lower numerically for K
but proportionally as a percentage of the mean they are lower for V

i think this means that v is more accurate

i want to know if im correct in saying this

1. 👍
2. 👎

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