Materials Science

A cube of aluminum contains 10^21 atoms. how long is its edge(in mm)?

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  1. Convert 10^21 atoms to g using the atomic weight. Then convert it to volume using the density. Then take the cube root of the volume in cm^3.

    Moles = 10^21/6.02*10^23 = 1.661*10^-3 moles

    Mass = 23 * 1.661*10^-3 = 0.0382 g

    Volume = 0.0382 g/2.70 g/cm^3 = 1.415*10^-2

    Edge Length = (1.415*10^-2)^1/3 = 0.24 cm

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