A large tank is filled with water to a depth of d = 18 m. A spout located h = 13 m above the bottom of the tank is then opened as shown in the drawing. With what speed will water emerge from the spout?

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  1. The pressure of water at the hole location is

    P = (rho)gH + Po

    where Po is atmospheric pressure

    The Bernoulli equation tells you that

    (1/2)(rho) V^2 = P - Po = (rho) g H

    The water density (rho) cancels out, so

    V = sqrt (2 g H)

    H is this case the the height of water ABOVE the hole, which is 5 m, not h=13 m

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  2. 9.8

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