what is the equation of the axis of symetry of the parabola represented by the equation y=2x^2+16x-11?
a)x=-8
b)x=8
c)x=-4
d)x=4
c) x=-4
To find the equation of the axis of symmetry for a parabola represented by the equation y = ax^2 + bx + c, we can use the formula x = -b/2a.
In the given equation y = 2x^2 + 16x - 11, we can identify that a = 2 and b = 16. Plugging these values into the formula, we have:
x = -(16)/(2 * 2)
x = -16/4
x = -4
Therefore, the equation of the axis of symmetry for the given parabola is x = -4.
So, the correct option is c) x = -4.