# math

Write the standard equation for the parabola with the given characteristics.
vertex:(0,0)
directrix:y= -1.

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1. The equation x^2 = 4 py is a parabola with vertex at (0,0) and a directrix below it at y = -p. You want p to be 1.

Therefore 4p = 1 and p = 1/4

y = x^2 /4 is the equation

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