chemistry

The Rydberg equation (1/lambda=R/ni^2–R/nf^2) can be treated as a line equation. What is the value of nf as a function of the slope (m) and y-intercept(b)?

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  1. 1/lambda = R/ni^2–R/nf^2
    y = mx + b (standard form) of a linear equation)
    x = (y-b)/m
    Let,
    y = 1/lambda
    m = -R
    x = 1/nf^2
    b = R/ni^2
    1/nf^2 = [(1/lamda)-(R/ni^2)]/(-R)
    Solve for nf

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    posted by GK
  2. These are the choices I can choose from:

    A. (mb)^1/2
    B. –mb^2
    C. mb
    D. (mb)^1/2
    E. (–mb)^1/2
    F. None of these are correct.

    And when I solve for what you give me, I don't seem to have any of the answers but F. And I wanted to know if that was correct.

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  3. nf would be the square root of some positive value, but your (A) and (B) look the same. Did you copy these alternate answers correctly?

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    posted by GK
  4. Yeah I copied the answers right.
    I don't see how answer A and B are the same.

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  5. (–m/b)^1/2 - so is this the answer?

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    posted by bob123

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