chemistry

The Rydberg equation (1/lambda=R/ni^2–R/nf^2) can be treated as a line equation. What is the value of nf as a function of the slope (m) and y-intercept(b)?

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1. 1/lambda = R/ni^2–R/nf^2
y = mx + b (standard form) of a linear equation)
x = (y-b)/m
Let,
y = 1/lambda
m = -R
x = 1/nf^2
b = R/ni^2
1/nf^2 = [(1/lamda)-(R/ni^2)]/(-R)
Solve for nf

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posted by GK
2. These are the choices I can choose from:

A. (mb)^1/2
B. –mb^2
C. mb
D. (mb)^1/2
E. (–mb)^1/2
F. None of these are correct.

And when I solve for what you give me, I don't seem to have any of the answers but F. And I wanted to know if that was correct.

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3. nf would be the square root of some positive value, but your (A) and (B) look the same. Did you copy these alternate answers correctly?

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posted by GK
4. Yeah I copied the answers right.
I don't see how answer A and B are the same.

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5. (–m/b)^1/2 - so is this the answer?

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posted by bob123

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