You have 2.0 g of solid A, 100.00 mL of water (100.0 g of water), and the total mass of solid A combined with 100.00 mL of water is found to be 102.0 g. The mass percent of A in this solution is

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  1. Mass percent is defined as # grams solute per 100 g solution and that times 100.
    So you have 2 g solute and 102 g of solution. Ergo!

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  2. @ DrBob222, i tried your way already and it didn't work.

    2/102 x100=1.96 can you double check again

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  3. You have done it correctly. What you may not have done (especially if you are checking your answer through a data base AND if your prof is picky about significant digits) is to round.
    (2.0/102.0)*100 = 1.96078, which to two s.f. (all you are allowed with the 2.0 value) rounds to 2.0%

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