while driving his sports car at 20.0 m/s down a four-lane highway, eddie comes up behind a slow-moving dump truck and decides to pass it in the left lane. If eddie can accelerate at 5.00 m/s2) (squared) how long will it take for him to reach a speed of 30.0 m/s?
v = 30m/s u = 20m/s a = 5m/s2 t = ?
v = u + at
30 = 20 + 5*t
30-20 = 5t
10 = 5t
10/5 = t
t=2s
I dont understand
Given : a = 5.00 m/s^2
vi = 20.0 m/s
vf = 30.0 m/s
Unknown: delta(t)
equation: a = (vf - vi) / delta(t)
solve: delta(t) = 10m/s / 5m/s^2 = 2 secs
while driving his sports car at 20.0 m/s down a four-lane highway, eddie comes up behind a slow-moving dump truck and decides to pass it in the left lane. If eddie can accelerate at 5.00 m/s2) (squared) how long will it take for him to reach a speed of 30.0 m/s?
Well, Eddie seems to have a need for speed! Let's see how quickly he can rev up that sports car.
To calculate the time it takes for Eddie to reach a speed of 30.0 m/s, we can use the equation:
v = u + at
Where:
v = final velocity (30.0 m/s)
u = initial velocity (20.0 m/s)
a = acceleration (5.00 m/s^2)
t = time
Rearranging the equation, we have:
t = (v - u) / a
Substituting the given values, we get:
t = (30.0 m/s - 20.0 m/s) / 5.00 m/s^2
Calculating it out, we find:
t = 10.0 m/s / 5.00 m/s^2
t = 2.0 s
So, Eddie will take about 2.0 seconds to go from 20.0 m/s to 30.0 m/s. Just enough time for him to enjoy a quick adrenaline rush and give the dump truck driver a thumbs-up!
To find the time it will take for Eddie to reach a speed of 30.0 m/s while accelerating at 5.00 m/s², we can use the equation of motion:
v = u + at
Where:
v = final velocity (30.0 m/s)
u = initial velocity (20.0 m/s)
a = acceleration (5.00 m/s²)
t = time
First, rearrange the equation to solve for time (t):
t = (v - u) / a
Substituting the given values:
t = (30.0 m/s - 20.0 m/s) / 5.00 m/s²
t = 10.0 m/s / 5.00 m/s²
t = 2.0 s
Therefore, it will take Eddie 2.0 seconds to reach a speed of 30.0 m/s while accelerating at 5.00 m/s².
vfinal=vinitial + acceleration*time
solve for time.