Algebra

(2x^3)-(14x^2)+12x=0
x=?

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asked by Kimba
  1. First, factor out the common 2x.
    This leaves you with
    2x[x^2 -6x +6) = 0

    x=0 is one solution. The others are the two roots of
    x^2 -6x +6 = 0,
    which are not integers. You can compute them with the quadratic equation

    x = [6 +/- sqrt(12)]/2 = 3 +/- sqrt3

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    posted by drwls

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