Hi there, I am having a problem with this question, any help would be great.
Use the following balanced chemical equation to calculate the mass of carbon dioxide produced from the burning of 5.50 kg of jet fuel which can be represented by the molecule C12H26. You should quote your answer
to 3 significant figures in units of kg. The relative atomic masses (RAMs) needed to do this calculation are as follows
RAM (carbon) = 12.0; RAM (oxygen) = 16.0; and RAM (hydrogen) = 1.01.
2 C12H26 + 37 O2 = 24 CO2 + 26 H2O
1. Write the equation and balance it.
2. Convert 5.5 kg to moles of jet fuel. # moles = grams/molar mass.
3. Using the coefficients in the balanced equation, convert moles of the jet fuel to moles of the product (in this case CO2).
4. Now convert moles CO2 to grams.
grams = moles x molar mass.
Post your work if you get stuck.
To calculate the mass of carbon dioxide produced from the burning of 5.50 kg of jet fuel (C12H26), you need to use the balanced chemical equation provided. The equation shows that 2 molecules of C12H26 react with 37 molecules of O2 to produce 24 molecules of CO2.
To calculate the mass of carbon dioxide produced, you can use the molar ratio between C12H26 and CO2. This ratio can be determined by comparing the coefficients in the balanced chemical equation. In this case, the ratio is 2:24.
First, calculate the molar mass of C12H26:
12.0 (carbon) + 26 * 1.01 (hydrogen) = 12.0 + 26.26 = 38.26 g/mol
Next, calculate the number of moles of C12H26 in 5.50 kg:
mass = moles * molar mass
moles = mass / molar mass
moles = 5500 g / 38.26 g/mol = 143.49 mol
Now, using the molar ratio 2:24, calculate the number of moles of CO2 produced:
moles of CO2 = moles of C12H26 * (24/2) = 143.49 mol * 12 = 1721.88 mol
Finally, calculate the mass of CO2 produced:
mass = moles * molar mass
mass = 1721.88 mol * (12 + 16) g/mol = 1721.88 mol * 28 g/mol = 48144.64 g = 48.145 kg
Therefore, the mass of carbon dioxide produced from the burning of 5.50 kg of jet fuel is 48.145 kg (rounded to 3 significant figures).