Hello, I am having a bit of trouble with two Algebra questions
1. Solve x= 8x - over the domain [0, 2, 4, 6]
2. For what values of a is the equation /a/ =5 true?
Thanks in advance.
1. x can only equal 8x if x = 0
(no matter what the domain is)
2. 5 and -5
Hello! I can help you with your algebra questions. Let's solve them step by step.
1. Solve x = 8x over the domain [0, 2, 4, 6]:
To solve this equation, we want to find the value(s) of x that make the equation true.
Start by subtracting 8x from both sides of the equation:
x - 8x = 0
Combining like terms gives us:
-7x = 0
Now, divide both sides by -7 to isolate x:
-7x / -7 = 0 / -7
x = 0
Therefore, the solution to the equation x = 8x over the domain [0, 2, 4, 6] is x = 0.
2. For what values of a is the equation |a| = 5 true:
The equation |a| = 5 means that the absolute value of a is equal to 5.
To solve this equation, we need to consider two cases:
Case 1: a is positive:
In this case, a itself will be 5 since the absolute value of any positive number is the number itself.
So, a = 5 is a solution.
Case 2: a is negative:
In this case, a will be -5 since the absolute value of any negative number is the positive version of that number.
So, a = -5 is also a solution.
Therefore, the values of a that make the equation |a| = 5 true are a = 5 and a = -5.
I hope this helps! Let me know if you have any further questions.