A bus travels 280 km south along a straight path with an average velocity of 88 km/hr to the south. The bus stops for 24 min, then it travels 210 km south with an average of 75 km/hr to the south.
A. How long does the total trip last?
B. What is the average velocity for the total trip?
I know this problem uses the average velocity equation, where the average velocity equals the change in position over the change in time, but I'm unsure which numbers I need to plug in. Please help!
So for part A, I got 6.38 hours because I added 3.18, 2.8 (210 km/75) and .40 together. Is this correct?
Ok good. Then, for part B...I got 76.8 for the average velocity.
...I sure hope this is correct...!
But drawls how 0.60 comes there....?
Yes, if the answer is in hours
To find the answer to this question, we will use the formula for average velocity, which is:
Average velocity = total displacement / total time
A. To find the total trip duration, we need to calculate two parts of the journey separately, the time it takes for the first leg and the time for the second leg.
1. Calculate the time for the first leg:
Distance traveled for the first leg = 280 km
Average velocity for the first leg = 88 km/hr
To find the time for the first leg, we can use the formula: time = distance / velocity
Time for the first leg = 280 km / 88 km/hr
2. Calculate the time for the second leg:
Distance traveled for the second leg = 210 km
Average velocity for the second leg = 75 km/hr
Similarly, we can find the time for the second leg: time = distance / velocity
Time for the second leg = 210 km / 75 km/hr
Now, to find the total trip duration, we can add the time for the first and second legs, along with the time the bus stopped:
Total trip duration = time for first leg + time stopped + time for second leg
Since the time stopped is given as 24 minutes, we need to convert it to hours by dividing by 60 minutes.
B. To find the average velocity for the total trip, we need to calculate the total displacement.
Total displacement = final position - initial position
The final position for the total trip is the position after the second leg, which is 280 km + 210 km = 490 km to the south. The initial position is 0 km.
Average velocity = total displacement / total time
Now, you can use the formulas and calculations to find the answers to both questions.
A. Add up the times spent travelling and at the intermediate 24 minute (0.40 hour) stop. The 280 km travled at 88 km/hr required 280/88 = 3.18 hours, for example.
Total time = 3.18 + 0.60 + ___ = hrs ?
B. For average velocity, divided the total distance traveled by the total time required (from part A). Both times spent travelling were in the same direction (South), ao you don't have to worry about adding vectors
a)6.38h
b)54.3