A 0.09 kg ball of dough is thrown straight up into the air with an initial speed of 5.5 m/s.
(a) Find the momentum of the ball of dough at its maximum height.
(b) Find the momentum of the ball of dough halfway to its maximum height on the way up.
To find the momentum of the ball of dough, we need to use the formula:
Momentum = mass * velocity
First, we need to find the velocity of the ball of dough at its maximum height and halfway to its maximum height.
(a) To find the velocity at the maximum height, we know that the ball is thrown straight up, so its velocity will decrease until it comes to a stop at the top of its trajectory. At this point, the velocity will be 0 m/s.
(b) To find the velocity halfway to the maximum height, we need to find the average velocity. This can be found by dividing the initial velocity by 2 since the velocity decreases linearly. So the average velocity halfway to the maximum height is 5.5 m/s / 2 = 2.75 m/s.
Now let's calculate the momentum for each case.
(a) Momentum at the maximum height: Since the velocity is 0 m/s at the maximum height, the momentum will also be 0.
(b) Momentum halfway to the maximum height: We will use the equation Momentum = mass * velocity. Given that the mass is 0.09 kg and the velocity is 2.75 m/s, we can calculate:
Momentum = 0.09 kg * 2.75 m/s = 0.2475 kg·m/s
Therefore, the momentum halfway to the maximum height is 0.2475 kg·m/s.
A 1.5
B. 1.5