Train A and B are traveling in the same direction on parallel tracks. Train A is traveling at 100 mph and B is traveling at 120 mph. Train A passes a station at 9:10 pm. If train B passes the same station at 9:25pm what time will train B catch up with train A?
To find out what time Train B will catch up with Train A, we need to calculate the time it takes for Train B to cover the distance that Train A has already traveled.
Let's consider the time difference when Train B passes the station at 9:25 pm. At this time, Train A has already been traveling for 15 minutes (9:25 pm - 9:10 pm).
In 15 minutes, Train A covers a distance of (15/60) * 100 = 25 miles (since it travels at 100 mph).
Now, the relative speed between the two trains is the difference in their speeds, which is 120 mph - 100 mph = 20 mph.
To catch up with Train A, Train B needs to cover the same 25 miles that Train A covered in 15 minutes.
Using the formula distance = speed * time, we can calculate the time it takes for Train B to catch up:
25 miles = 20 mph * time
Simplifying the equation:
time = 25 miles / 20 mph
time = 5/4 hours
time = 1.25 hours
So, Train B will catch up with Train A 1.25 hours after it passes the station at 9:25 pm.
To find out the specific time, we add 1.25 hours to the time Train B passed the station:
9:25 pm + 1.25 hours = 10:30 pm
Therefore, Train B will catch up with Train A at 10:30 pm.