1. Review the graphs of a system of two linear equations in two variables: x − 5y = 7 and 3x − 2y = −4. Find the solution to both equations.
On a graph there's 3x - 2y = -4 and x - 5y = 3.
The intersection point is (____).
2. Review the graphs of a system of two linear equations in two variables: 4x + 3y = 15 and y = x + 5. Find the solution to both equations.
On a graph there's 4x + 3y = 15 and y = x + 5.
The intersection point is (____).
the answer is a number not a fraction
the answer has to look like (____),( ____)
it is not correct
1. Review the graphs of a system of two linear equations in two variables: x − 5y = 7 and 3x − 2y = −4. Find the solution to both equations.
On a graph there's 3x - 2y = -4 and x - 5y = 3.
The intersection point is (____), (____).
The correct solution is (3, 2).
1. Review the graphs of a system of two linear equations in two variables: x − 5y = 7 and 3x − 2y = −4. Find the solution to both equations.
The intersection point is (____), (____).
how bout now?
The intersection point is (3, -2).
1. The intersection point of the graphs of x - 5y = 7 and 3x - 2y = -4 is (3, -2). This means the solution to both equations is x = 3 and y = -2.
2. The intersection point of the graphs of 4x + 3y = 15 and y = x + 5 is (5, 10). This means the solution to both equations is x = 5 and y = 10.
1. The intersection point of the graphs of x − 5y = 7 and 3x − 2y = −4 is (3, -1). This means the solution to both equations is x = 3 and y = -1.
2. The intersection point of the graphs of 4x + 3y = 15 and y = x + 5 is (4, 9). This means the solution to both equations is x = 4 and y = 9.
1. The intersection point of the graphs of x − 5y = 7 and 3x − 2y = −4 is (3, -1).
2. The intersection point of the graphs of 4x + 3y = 15 and y = x + 5 is (4, 9).
I apologize for the oversight. Let's find the correct intersection points:
1. Intersection point of x - 5y = 7 and 3x - 2y = -4:
From the first equation:
x = 5y + 7
Substitute into the second equation:
3(5y + 7) - 2y = -4
15y + 21 - 2y = -4
13y + 21 = -4
13y = -25
y = -25/13
x = 5(-25/13) + 7
x = -125/13 + 91/13
x = -34/13
Therefore, the intersection point is (-34/13, -25/13).
2. Intersection point of 4x + 3y = 15 and y = x + 5:
Substitute y = x + 5 into the first equation:
4x + 3(x + 5) = 15
4x + 3x + 15 = 15
7x = 0
x = 0
Now, substitute x = 0 back into y = x + 5:
y = 0 + 5
y = 5
Therefore, the intersection point is (0, 5).