Trains A and B are traveling in the same direction on parrallel tracks. Train A is traveling at 60 mph, and train B is traveling at 80 mph. Train A passes a station at 11:15 a.m. if train B passes the same station at 11:30 a.m. at what time will train B catch up to train A?
When will train B catch up to train A?
__:__ (a.m / p.m)
Word problems are not my best quality,can someone please help me figure out the formula and how to solve this question>>> Thanks
To solve this question, you can use the formula:
Time = Distance / Speed
First, let's find the distance traveled by train A during the time between when it passes the station and when train B passes the station. Since train A travels for 15 minutes (from 11:15 a.m. to 11:30 a.m.) and its speed is 60 mph, we can calculate:
Distance of Train A = Speed of Train A × Time
= 60 mph × (15/60) hours
= 15 miles
Now, let's focus on finding out the time it takes for train B to catch up to train A. Since both trains are traveling in the same direction, the relative speed of train B with respect to train A would be the difference in their speeds, which is 80 mph - 60 mph = 20 mph.
Now, we can use the formula Time = Distance / Speed, but since we want to find the time at which train B catches up to train A, we will use distance as the distance traveled by train A, which we calculated earlier as 15 miles.
Time taken by train B to catch up = Distance of Train A / Relative speed of Train B
= 15 miles / 20 mph
= 0.75 hours
= 45 minutes
Therefore, train B will catch up to train A 45 minutes after train A passes the station. Adding this to the time when train A passes the station (11:15 a.m.), we can calculate the time when train B catches up to train A:
11:15 a.m. + 0 hours 45 minutes = 12:00 p.m.
Therefore, train B will catch up to train A at 12:00 p.m.