Can you help me balance some equations? I tried and failed several times...
1. calcium hydroxide + phosphoric acid yield calcium phosphate + water
2. copper + sulfuric acid yield copper(II) Sulfate + water + sulfur dioxide
3. hydrogen + nitrogen monoxide yield water + nitrogen
Thank you SOOO MUCH
A good place to start would be writing the formulas of each compound. THEN start balancing. For reaction #2, your reactants are Cu and H2SO4 and the products are CuSO4 and H2. That's an easy one; it is balanced already. The SO4(--) from the acid joins the Cu, and the H2 is released.
Cu + H2SO4 -> H2 + CuSO4
Of course! I'd be happy to help you balance these chemical equations. Balancing equations is a process of ensuring that the number of atoms on both sides of the equation is equal. Here's how you can balance each equation:
1. Calcium hydroxide + phosphoric acid -> calcium phosphate + water
Let's start by counting the number of atoms on each side of the equation:
Calcium (Ca) - 1 atom on the left, 1 atom on the right
Hydrogen (H) - 2 atoms on the left, 0 atoms on the right
Oxygen (O) - 2 atoms on the left, 4 atoms on the right
Phosphorus (P) - 1 atom on the left, 1 atom on the right
To balance the equation, we can start by balancing the atoms that occur in the fewest compounds. In this case, let's balance the phosphorus (P) atoms first:
Ca(OH)2 + H3PO4 -> Ca3(PO4)2 + H2O
Now, let's balance the hydrogen (H) atoms by adding coefficients to the appropriate compounds:
3Ca(OH)2 + 2H3PO4 -> Ca3(PO4)2 + 6H2O
Finally, let's balance the oxygen (O) atoms:
3Ca(OH)2 + 2H3PO4 -> Ca3(PO4)2 + 6H2O
Now the equation is balanced!
2. Copper + sulfuric acid -> copper(II) sulfate + water + sulfur dioxide
Let's count the atoms again:
Copper (Cu) - 1 atom on the left, 1 atom on the right
Hydrogen (H) - 0 atoms on the left, 2 atoms on the right
Oxygen (O) - 4 atoms on the right
Sulfur (S) - 1 atom on the right
To balance the equation, let's start by balancing the sulfur (S) atom:
Cu + H2SO4 -> CuSO4 + H2O + SO2
Next, balance the hydrogen (H) atoms:
Cu + H2SO4 -> CuSO4 + 2H2O + SO2
Finally, balance the oxygen (O) atoms:
Cu + H2SO4 -> CuSO4 + 2H2O + SO2
Now the equation is balanced!
3. Hydrogen + nitrogen monoxide -> water + nitrogen
Let's count the atoms:
Hydrogen (H) - 2 atoms on the left, 2 atoms on the right
Oxygen (O) - 1 atom on the left, 1 atom on the right
Nitrogen (N) - 1 atom on the right
The equation is already balanced for hydrogen and oxygen, but we need to balance the nitrogen (N) atom:
2H2 + 2NO -> 2H2O + N2
Now the equation is balanced!
I hope this helps you balance the equations! Let me know if you have any further questions.