A letter is to be picked at random from the English alphabet. If each letter is equally likely to be selected, what is the probability of selecting a consonant? Consonants are letters except for a, e, i, o, and u. Write your answer in the simplest form of fraction.(1 point)
A survey was conducted to determine students’ preferred learning style. The distribution of responses from the sample participants are summarized as follows: Learning Styles Number of Students Who Prefer Each Style auditory learning style 17 visual learning style 20 kinesthetic learning style 13 Write a ratio that compares the number of students who preferred a visual learning style to the number of student-participants of the survey. Write your answer in the simplest fraction form.(1 point) Responses 2/3 Start Fraction 2 over 3 End Fraction 2/5 Start Fraction 2 over 5 End Fraction 3/5 Start Fraction 3 over 5 End Fraction 20
The ratio that compares the number of students who preferred a visual learning style to the number of student-participants of the survey is:
20 (number of students who preferred visual learning style) : 50 (total number of students surveyed)
This can be simplified by dividing both sides by 10:
2 : 5
So, the ratio in the simplest form is 2/5.
Therefore, the correct answer is:
2/5 (Start Fraction 2 over 5 End Fraction)
Each letter of the word movers is written on an individual paper strip and placed in a box. Which set represents the favorable outcomes of the event of randomly choosing a consonant letter?(1 point) Responses {o, e} {o, e} {v, r, s} {v, r, s} {m, v, r, s} {m, v, r, s} {m, o, v, e, r, s}
The word "movers" includes the letters: m, o, v, e, r, s.
The consonant letters are: m, v, r, s.
Therefore, the set that represents the favorable outcomes of randomly choosing a consonant letter is:
{m, v, r, s}
Calculate the theoretical probability of choosing an even-numbered card from a traditional deck of 52 cards. For this question, face cards are not counted as odd or even. Simplify.(1 point) Responses 5/13 Start Fraction 5 over 13 End Fraction 7/13 Start Fraction 7 over 13 End Fraction 20/52 Start Fraction 20 over 52 End Fraction 4/13 Start Fraction 4 over 13 End Fraction
In a traditional deck of 52 cards, there are 26 even-numbered cards (2, 4, 6, 8, 10) out of the total 52 cards.
The theoretical probability of choosing an even-numbered card is:
26 even-numbered cards / 52 total cards = 1/2
This probability can be simplified further:
1/2 = 2/4 = 13/26
Therefore, the simplified answer is:
13/26 or 1/2
So, the theoretical probability of choosing an even-numbered card from a traditional deck of 52 cards is 1/2 or 13/26.
Responses 5/13 Start Fraction 5 over 13 End Fraction 7/13 Start Fraction 7 over 13 End Fraction 20/52 Start Fraction 20 over 52 End Fraction 4/13 Start Fraction 4 over 13 End Fraction
The theoretical probability of choosing an even-numbered card from a traditional deck of 52 cards is 1/2. This can be simplified to the fraction 26/52 which simplifies to 1/2.
In fraction form, this is equivalent to 1/2.
None of the given answer options match this value, so based on the choices provided, the closest option is:
20/52 which simplifies to 5/13
Therefore, the closest option from the choices given is:
5/13 (Start Fraction 5 over 13 End Fraction)
Use the image to answer the question. (Numbers: 22, 25, 28, 1, 4, 7, 10, 13, 16, 19.)If this spinner is to be spun once, how likely will it stop on a multiple of 9? (1 point) Responses unlikely unlikely impossible impossible likely likely certain certain
None of the numbers provided in the set {22, 25, 28, 1, 4, 7, 10, 13, 16, 19} are multiples of 9.
Therefore, if the spinner is to be spun once, it is impossible for it to stop on a multiple of 9.
So, the correct response is "impossible."
There are 26 letters in the English alphabet.
There are 21 consonants (all except a, e, i, o, u).
Therefore, the probability of selecting a consonant is 21/26.
This can be simplified to be 3/4.
So, the probability of selecting a consonant is 3/4.