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When hydrochloric acid reacts with magnesium metal, hydrogen gas and aqueous magnesium chloride are produced. What volume of 5.0 M HCI is required to react completely with 3.00 g of magnesium?

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Angel

  1. The Chemical reaction is:
    Mg + 2HCl --> MgCl2 + H2

    1) Divide the grams of Mg by the atomic mass of Mg to get moles of Mg.
    2) Moles of HCl = (2)(moles of Mg)
    3) Moles of HCl = (V)(5.0 mol/L)
    or
    Volume of HCl = (mol. HCl) / (5.0 mol/L)
    ---------
    NOTE: The volume of HCl will be in liters

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    GK

  2. If 5.00 g of manganese (IV) oxide reacts with 25.0 mL of 6.00 M hydrochloric acid, what is the calculated mass of chlorine gas produced?

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    Anonymous

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