Phyics

1)A logging truck is dragging a 427 kg log through the forest at a constant speed of 3.5 m/s. If the truck is applying a force of 1047 N to the log to keep it moving, what is the coefficient of friction between the log and the ground?
im thinking you use the kinetic friction= μk(normal force) equation so does that mean it would be 3.5 m/s=μ(1047N) but then where does the 427 kg come in??

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asked by Anonymous
  1. The speed has nothing to do with it. You just need to know that it is constant. That means the net force is zero.
    Towing force = Friction force
    1047 N = M*g*μk
    = 427*9.8*μk
    Solve for μk

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    posted by drwls

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