Find all real values of x such that f(x) = 0
f(x) = 3 + 1
x – 2
Look at the way your equation came out.
It makes no sense.
Please retype using brackets.
To find the real values of x such that f(x) = 0, we need to solve the equation
f(x) = 3 + 1/(x-2) = 0.
Rearranging the equation, we have
1/(x-2) = -3.
To solve this equation, we can multiply both sides by (x-2), giving
1 = -3(x-2).
Distributing -3 on the right side,
1 = -3x + 6.
Next, we isolate the x term by subtracting 6 from both sides,
-5 = -3x.
Finally, we solve for x by dividing both sides by -3,
-5/-3 = x.
Simplifying,
5/3 = x.
Therefore, the only real value of x that satisfies the equation f(x) = 0 is x = 5/3.