Before investigating the scene, the technician must dilute the luminol solution to a concentration of 4.00×10−2 . The diluted solution is then placed in a spray bottle for application on the desired surfaces.
How many moles of luminol are present in 2.00 L of the diluted spray?
molarity x liters = moles.
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To calculate the number of moles of luminol present in 2.00 L of the diluted spray, you need to use the concentration of the solution.
Given:
Volume of solution (V) = 2.00 L
Concentration of luminol solution (C) = 4.00×10^−2 M
To find moles (n), you can use the formula:
n = C x V
Plugging in the values:
n = (4.00×10^−2 M) x (2.00 L)
n = 0.08 moles
Therefore, there are 0.08 moles of luminol present in 2.00 L of the diluted spray.
To find the number of moles of luminol present in 2.00 L of the diluted spray, we need to use the given concentration of the solution. The concentration is given as 4.00 × 10^-2, which can be expressed as 4.00 × 10^-2 moles per liter (mol/L).
We can use the formula to calculate the number of moles:
Moles = Concentration × Volume.
Plugging in the given values:
Moles = (4.00 × 10^-2 mol/L) × (2.00 L).
Moles = 8.00 × 10^-2 mol.
Therefore, there are 8.00 × 10^-2 moles of luminol present in 2.00 L of the diluted spray.