A person has a reasonable chance of surviving an automobile crash if the deceleration is no more than 30 "g's" (recall that g = 9.8 m/s2). Calculate the force, in N, on a 68 kg person accelerating at this rate.
30"g" x 9.8
294 ms^2
f=ma
294x68
=19,992N
I don't see anything wrong with your calculations.
I don't even want to try 1 g (falling on my face), much less 30g. However, that's where air-bags come in, I guess.
To calculate the force on a person accelerating at a rate of 30 "g's", follow these steps:
1. Convert the acceleration from "g" to m/s^2. Remember that 1 "g" is equal to 9.8 m/s^2. Multiply the given value of 30 "g's" by 9.8 to get the acceleration in m/s^2:
30 "g" x 9.8 = 294 m/s^2
2. Use Newton's second law of motion, which states that force (F) is equal to mass (m) multiplied by acceleration (a). In this case, the mass of the person is given as 68 kg. Multiply the mass by the acceleration to get the force:
Force (F) = mass (m) x acceleration (a)
Force = 68 kg x 294 m/s^2
Force ≈ 19,992 N
Therefore, the force on a 68 kg person accelerating at a rate of 30 "g's" is approximately 19,992 N.