Suppose you wanted to dissolve an aluminum block with a mass of 15.4 g

What mass of H2 gas (in g) would be produced by the complete reaction of the aluminum block?.

2Al + 6HCl ==> 2AlCl3 + 3H2

Convert 15.4 g Al to moles. moles = grams/molar mass
Convert moles Al to moles H2 using the coefficients in the balanced equation.
Convert moles H2 gas to grams. grams = moles x molar mass.

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To calculate the mass of H2 gas produced by the complete reaction of the aluminum block, we need to use the balanced chemical equation for the reaction between aluminum and hydrochloric acid.

The balanced chemical equation is:
2Al + 6HCl -> 2AlCl3 + 3H2

From the equation, we can see that 2 moles of aluminum react with 3 moles of hydrogen gas. The molar mass of aluminum is 26.98 g/mol, so the number of moles of aluminum in 15.4 g can be calculated as:

moles of aluminum = mass of aluminum / molar mass of aluminum
moles of aluminum = 15.4 g / 26.98 g/mol

Next, we can use the mole ratio from the balanced equation to find the number of moles of hydrogen gas produced:

moles of H2 = (moles of aluminum) * (3 moles of H2 / 2 moles of Al)

Finally, we can calculate the mass of hydrogen gas using the molar mass of hydrogen (2.02 g/mol):

mass of H2 = moles of H2 * molar mass of H2

Now we can plug in the values to find the mass of H2 gas produced:

moles of aluminum = 15.4 g / 26.98 g/mol
moles of H2 = (moles of aluminum) * (3 moles of H2 / 2 moles of Al)
mass of H2 = moles of H2 * molar mass of H2

Let's do the calculations:
moles of aluminum = 15.4 g / 26.98 g/mol = 0.571 mol
moles of H2 = (0.571 mol) * (3 mol H2 / 2 mol Al) = 0.857 mol
mass of H2 = 0.857 mol * 2.02 g/mol = 1.731 g

Therefore, the mass of H2 gas produced by the complete reaction of the aluminum block is approximately 1.731 grams.

To determine the mass of H2 gas produced by the complete reaction of the aluminum block, we need to know the balanced chemical equation for the reaction. The reaction between aluminum (Al) and hydrochloric acid (HCl) is commonly used to produce hydrogen gas (H2). The balanced equation for this reaction is as follows:

2 Al(s) + 6 HCl(aq) → 2 AlCl3(aq) + 3 H2(g)

From the equation, we can see that 2 moles of aluminum react with 6 moles of hydrochloric acid to produce 3 moles of hydrogen gas.

1. Determine the number of moles of aluminum:
Using the molar mass of aluminum (Al), which is approximately 26.98 g/mol, we can calculate the moles of aluminum.

Moles of aluminum = mass of aluminum (g) ÷ molar mass of aluminum (g/mol)
Moles of aluminum = 15.4 g ÷ 26.98 g/mol ≈ 0.57 mol

2. Determine the moles of hydrogen gas produced:
Since the molar ratio between aluminum and hydrogen gas is 2:3, we can use this ratio to calculate the moles of hydrogen gas.

Moles of hydrogen gas = Moles of aluminum × (3 mol H2 / 2 mol Al)
Moles of hydrogen gas = 0.57 mol × (3 mol H2 / 2 mol Al) ≈ 0.86 mol

3. Determine the mass of hydrogen gas:
To calculate the mass of hydrogen gas, we multiply the moles of hydrogen gas by its molar mass. The molar mass of hydrogen gas (H2) is approximately 2.02 g/mol.

Mass of hydrogen gas = moles of hydrogen gas × molar mass of hydrogen gas
Mass of hydrogen gas = 0.86 mol × 2.02 g/mol ≈ 1.74 g

Therefore, the mass of H2 gas produced by the complete reaction of the aluminum block is approximately 1.74 grams.