1580 kg car is traveling with speed of 15 m/s. What is magnitude of horizontal net force that's required to bring the car to a stop in 50 m?
force*distance= 1/2 masscar*15^2
solve for force.
342
3555n
To find the magnitude of the horizontal net force required to bring the car to a stop, we can use the equation:
Force = (Mass * Change in velocity) / Time
First, we need to find the change in velocity.
Given:
Initial velocity (u) = 15 m/s
Final velocity (v) = 0 m/s (as the car comes to a stop)
Change in velocity (∆v) = v - u = 0 - 15 = -15 m/s
Next, we need to find the time taken to stop the car.
Given:
Distance (s) = 50 m
Velocity (u) = 15 m/s
Using the formula:
s = (u + v) * t / 2
where t is the time taken,
50 = (15 + 0) * t / 2
Simplifying the equation,
50 = 15t / 2
50 * 2 = 15t
100 = 15t
t = 100 / 15
t ≈ 6.67 seconds
Now, we can calculate the magnitude of the horizontal net force:
Force = (Mass * Change in velocity) / Time
Given:
Mass (m) = 1580 kg
Change in velocity (∆v) = -15 m/s
Time (t) = 6.67 seconds
Plugging in the values:
Force = (1580 * -15) / 6.67
Force ≈ -3555.22 N
The magnitude of the horizontal net force required to bring the car to a stop is approximately 3555.22 N.