A rectangular field is to be enclosed with 1200 ft of fencing. If the length of the field is 40 ft longer than the width, then how long is the field?
2w + 2(w+40)=1200
solve for w, then solve for w+40
320
To find the length of the field, we need to set up an equation based on the given information. Let's assume that the width of the field is "w" ft.
The length of the field is given as 40 ft longer than the width, so it would be "w + 40" ft.
Since the field is rectangular, the perimeter is equal to the sum of all four sides.
The perimeter of a rectangle can be calculated by adding twice the length and twice the width.
We are given that the fence required to enclose the field is 1200 ft, so we can set up the following equation:
2(w + 40) + 2w = 1200
Simplifying the equation, we get:
2w + 80 + 2w = 1200
Combining like terms, we have:
4w + 80 = 1200
Subtracting 80 from both sides of the equation, we get:
4w = 1120
Dividing both sides by 4, we have:
w = 280
Hence, the width of the field is 280 ft.
Now, to find the length, we can substitute the value of w back into the equation:
length = w + 40
length = 280 + 40
length = 320
Therefore, the length of the field is 320 ft.