Consider the following mixture of SO2(g) and O2(g).If SO2(g) and O2(g) react to form SO3(g),draw a representation of the product mixture assuming the reaction goes to completion. What is the limiting reactant in the reaction? If 96.0 g of SO2 reacts with 32.0 g O2, what mass of product will form?

The reaction is
2 SO2 + O2 -> 2 SO3

32 g of O2 is 1 mole, and that would require 2 moles (128 g) of SO2 to react completely. If you only have 96 g (1.5 moles) of SO2, that is the limiting reactant. 1.5 moles of SO3 would form, and you can figure out the mass from that.

  1. 👍 2
  2. 👎 0
  3. 👁 1,142
  1. 120g

    1. 👍 0
    2. 👎 0

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