X^2 + 6 = -8x..........Isn't this quadratic?
sure is,
take the -8x to the left side
x^2 + 8x + 6 = 0
about as quadratic as they get!
Thank you...I think that I finally got it!!!
this math stuff;-)
Yes, the equation you provided, X^2 + 6 = -8x, is a quadratic equation. A quadratic equation is a polynomial equation of degree 2, which means the highest power of the variable is 2. In this case, the variable is X, and we have the term X^2, indicating a quadratic equation.
To solve this quadratic equation, we need to rearrange it into a standard form, which is ax^2 + bx + c = 0, where a, b, and c are constants.
Let's bring all the terms to one side of the equation:
X^2 + 8X + 6 = 0
Now, using the quadratic formula, we can find the value(s) of X that make this equation true. The quadratic formula is given by:
X = (-b ± √(b^2 - 4ac)) / (2a)
In this case, a = 1, b = 8, and c = 6. Substituting the values into the formula, we get:
X = (-8 ± √(8^2 - 4(1)(6))) / (2(1))
Simplifying further, we have:
X = (-8 ± √(64 - 24)) / 2
X = (-8 ± √40) / 2
X = (-8 ± 2√10) / 2
Now, we can simplify the expression:
X = -4 ± √10
So, the equation X^2 + 6 = -8x has two solutions: X = -4 + √10 and X = -4 - √10.