physics

Suppose an astronaut drops a feather from 1.4 m above the surface of the Moon. If the acceleration due to gravity on the Moon is 1.62 m/s2 downward, how long does it take the feather to hit the Moon's surface?

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  1. Ignore air resistance, which is justifiable in an insignificant atmosphere.

    S=ut+(1/2)at²
    u=initial velocity=0
    a=acceleration du to gravity=-1.62 m/s/s
    S=displacement = -1.4 m (downwards)
    t=time in seconds

    -1.4 = 0*t + (1/2)(-1.62)t²
    t=sqrt(2*1.4/1.62)
    =1.31 s.

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