Calculus
 👍
 👎
 👁

 👍
 👎

 👍
 👎
Respond to this Question
Similar Questions

Physics
I need help with this question with explanation. Thanks A particle of mass m starts from rest at position x = 0 and time t = 0. It moves along the positive xaxis under the influence of a single force Fx = bt, where b is a

Calculus
The Question: A particle moves along the Xaxis so that at time t > or equal to 0 its position is given by x(t) = cos(√t). What is the velocity of the particle at the first instance the particle is at the origin? So far I was

PHYSICS
A particle confined to motion along the x axis moves with constant acceleration from x = 2.0 m to x = 8.0 m during a 2.5s time interval. The velocity of the particle at x = 8.0 m is 2.8 m/s. What is the acceleration during this

calculus
A Particle moves along the xaxis so that at any time t>0, its acceleration is given by a(t)= ln(1+2^t). If the velocity of the particle is 2 at time t=1, then the velocity of the particle at time t=2 is? The correct answer is

12th grade
A particle starts at x=0 and moves along the xaxis with velocity v(t)=2t+1 for time t is less than or equal to 0. Where is the particle at t=4?

calculus
Consider a particle moving along the xaxis where x(t) is the position of the particle at time t, x'(t) is its velocity, and x''(t) is its acceleration. A particle moves along the xaxis at a velocity of v(t) = 5/√t, t > 0. At

math
a particle starts at time t = 0 and moves along the x  axis so that its position at any time t is greater than or equal to zero is given x(t) = (t1)^3(2t3) A. Find the velocity of the particle at any time t greater than or

Calculus
1) A particle is moving along the xaxis so that its position at t ≥ 0 is given by s(t) = (t)In(2t). Find the acceleration of the particle when the velocity is first zero. 2) The driver of a car traveling at 50 ft/sec suddenly

Calculus
A particle moves along the xaxis so that at any time t, measured in seconds, its position is given by s(t) = 5cos(t) − sin(3t), measured in feet. What is the acceleration of the particle at time t = π seconds?

Calculus
A particle starts at the point (5,0) at t=0 and moves along the xaxis in such a way that at time t>0 its velocity v(t) is given by v(t)= t/(1+t^2). a). Determine the maximum velocity of the particle. Justify your answer. b).

ap calculus
a particle moves along the x axis in such a way that its acceleration at time t, t>0 , is given by x(t)= (ln x)^2. at what value of t does the velocity of the particle attain its maximum

calculus
a particle moves along the y axis so that its position at any time t, for 0 is less than or equal to t which is less than or equal to 5, is given by y(t)=t^418t^2. in which intervals is the particle speeding up?
You can view more similar questions or ask a new question.