If you were to dissolve 14.00 grams of salicylic acid in enough water to make 400.00 mL of solution, what is the molarity of the final solution?

i did M = moles/L
so .1014 mol/.4000L = .2535 M

is this correct??

The next part of the question is

Now you take 50.00 mL of this solution and dilute it to 250.00 mL. What is the molarity.

I need help with this part. thankss

5 answers

I get 0.2534 M. The difference is that you rounded the 14.00/138.12 to 0.1014 whereas I left the number (0.10136) in the calculator before dividing by the 0.4000.

what about the other part?

Just use M1V1 = M2V2

thanks

To find the molarity of the final solution after dilution, you can use the equation:

M1V1 = M2V2

Where:
M1 = initial molarity
V1 = initial volume
M2 = final molarity
V2 = final volume

In this case, you already know the initial molarity is 0.2535 M (as calculated in the previous question) and the initial volume is 50.00 mL. The final volume is given as 250.00 mL.

Plug the values into the equation:

(0.2535 M)(50.00 mL) = (M2)(250.00 mL)

Rearrange the equation to solve for M2:

M2 = (0.2535 M)(50.00 mL) / (250.00 mL)

M2 = 0.0507 M

Therefore, the molarity of the final solution after dilution is 0.0507 M.