PRE-CALCULUS

AN OPEN BOX IS FORMED BY CUTTING SQUARES OUT OF A PIECE OF CARDBOARD THAT IS 16 FT BY 19 FT AND FOLDING UP THE FLAPS. WHAT SIZE CORNER SQUARES SHOULD BE CUT TO YEILD A BOX THAT HAS A VOLUME OF 175 CUBIC FEET

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  1. Let the side of the square to be cut out be x ft.
    The volume of the resulting box is then
    V = x(16-2x)(19-2x) = 175 ft³
    You can solve the equation by trial and error, there should be a root around x=0.68 ft.

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  2. V = x(16-2x)(19-2x) = 175 ft³

    Ok, thanks. Now I'm trying to multiply out and having some difficulty. I am getting 4x^3-70x^2+304x = 175 which I'm not sure how to work with

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  3. See response of follow-up post:
    http://www.jiskha.com/display.cgi?id=1252257020

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  4. 2.885

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