Can someone assist me in answering this question.
Use the given values of n and p to find the mimimum usual value of u-2standard deviations and the maximum ususual values u+20. n-186, p=0.13
To find the minimum usual value of u-2 standard deviations and the maximum usual value of u+2 standard deviations, we need to know the mean (u) and the standard deviation (s) of the population.
Given information:
n = 186 (sample size)
p = 0.13 (probability)
To find the minimum usual value (u-2s):
Step 1: Find the mean (u):
u = np
u = 186 * 0.13
u = 24.18 (rounded to two decimal places)
Step 2: Find the standard deviation (s):
s = √(np(1-p))
s = √(186 * 0.13 * (1 - 0.13))
s = √(186 * 0.13 * 0.87)
s = √(21.69)
s = 4.65 (rounded to two decimal places)
Step 3: Calculate the minimum usual value (u-2s):
minimum usual value = u - 2s
minimum usual value = 24.18 - 2 * 4.65
minimum usual value = 24.18 - 9.3
minimum usual value = 14.88 (rounded to two decimal places)
Therefore, the minimum usual value of u-2 standard deviations is approximately 14.88.
To find the maximum usual value (u+2s):
Step 4: Calculate the maximum usual value (u+2s):
maximum usual value = u + 2s
maximum usual value = 24.18 + 2 * 4.65
maximum usual value = 24.18 + 9.3
maximum usual value = 33.48 (rounded to two decimal places)
Therefore, the maximum usual value of u+2 standard deviations is approximately 33.48.
So, the minimum usual value of u-2 standard deviations is approximately 14.88, and the maximum usual value of u+2 standard deviations is approximately 33.48.