Chemistry

At 1100 K, Kp=0.25 for the following reaction. 2SO2(g) + O2(g) (reversible arrows) 2SO3(g) What is the value of K at this temperature?

This is what I have so far: I did Kc=0.25(1100(0.0821))^-1 and got Kc=0.00276. That is incorrect. Why? What did I do wrong?

I believe I gave you the wrong equation.
Kc = Kp(RT)^-delta n. My eyes aren't all that good and I think I just read it wrong. That would be 0.25(0.0821*1100)^1 = ??
Try that.

Let me know what you find.

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asked by Taasha
  1. Kp=Kc(RT)^delta(N)

    .25=Kc(.08206*1100)^(2-3)
    .25=Kc(90.27)^-1
    .25=Kc 1.108*10^-2
    divide both sides by 1.108*10^-2

    22.6=Kc
    it may be off a bit because i didn't account for significant figures

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    posted by sammy

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