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Factor completely
I am to factor this completely and I am stuck. 2r^3 + 8r^2 +6r Note: x^2 is xsquared (that is, x with the superscript 2), etc. 2 is a factor and r is a factor so the equation becomes 2r(r^2 + 4r + 3) then we can factor the term
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how do i solve this equation? there is another answer other than 0, but i am not sure how to get it. 5x^2 + 7x =0 factor the term: x(5x+7)=0 Either term can be zero. You found the x=0, what value of x makes 5x+7 zero? Factor it to
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Factor by identifying a common factor in each term. g) 6xy2 = (3x) (?) h) 25a3b2 = (5a2b2) (?) i) 6x + 6y + 6p Factor: j) x(x+2) + y (x + 2)  5(x + 2) k) 5y2  10y3 l) ax + ay + az Factor: m) yx(y+1) + 4x(y + 1)  5(y + 1) n) 6p2
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How do you factor this completly 7x*(4x5)^3+(4x5)^4 I am confused by the different power of exponets and the 7x in front Can you please help me? 7x*(4x5)^3+(4x5)^4 factor out the common term: (4x5)^3 * (7x+4x5) Then simplify
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How do you factor 2x^25x+2? (x2)(2x1) how do you figure that out? trinomials like that can usually be done intuitively, but you should have been taught a method that you can use for general cases. Look at the first term of 2x^2
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Rewrite the middle term as the sum of two terms and then factor completely. x2 + 19x + 90 Factor completely. ax – ay + x2 – xy Rewrite the middle term as the sum of two terms and then factor by grouping. x2 + 4x – 12
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