I'm having a trouble with this question. "Calculate the concentration of the Solute in mol/L in :
a) 125 mL of .64M HCl diluted to 2.0L
mole/L is what you want.
How much do you have?
0.125 L x 0.64 M = 0.195 moles.
So you have 0.195 moles/2 L = ?? moles/1 L.
To calculate the concentration of the solute in mol/L in this question, you need to use the dilution formula, which is:
C1V1 = C2V2
Here's how to calculate the concentration of the solute in mol/L:
1. Identify the given values:
- Initial concentration (C1) = 0.64M
- Initial volume (V1) = 125 mL = 0.125 L (converted to liters)
- Final volume (V2) = 2.0 L
2. Plug in the values into the dilution formula:
0.64M * 0.125 L = C2 * 2.0 L
3. Solve for C2 (the final concentration):
(0.64M * 0.125 L) / 2.0 L = C2
4. Calculate the result:
C2 = 0.04 M
Therefore, the concentration of the solute in mol/L in the given solution is 0.04 M.