Solve equation using quadratic formula
x^2+4x+3=0
is answer 3,1 ?
Remember that it is (-b +/- sqrt (b^2 - 4ac))/2a. Try again using -b.
Im not getting it.
x2+4x+3 = 0
(x+1)(x+3) = 0
x+1=0 or x+3=0
...
Sorry, reread the message from Marth. I didn't notice the requirement to use the quadratic formula.
To solve the given equation using the quadratic formula, follow these steps:
1. Identify the coefficients: The equation is in the form of ax^2 + bx + c = 0, where a, b, and c are coefficients. In this case, a = 1, b = 4, and c = 3.
2. Apply the quadratic formula: The quadratic formula states that for an equation in the form ax^2 + bx + c = 0, the solutions for x can be found using the formula:
x = (-b ± √(b^2 - 4ac)) / (2a)
3. Substitute the values: Substitute the values of a, b, and c into the quadratic formula:
x = (-(4) ± √((4)^2 - 4(1)(3))) / (2(1))
Simplifying further:
x = (-4 ± √(16 - 12)) / 2
x = (-4 ± √4) / 2
x = (-4 ± 2) / 2
4. Evaluate the solutions: Calculate both solutions:
Solution 1: x = (-4 + 2) / 2 = -2 / 2 = -1
Solution 2: x = (-4 - 2) / 2 = -6 / 2 = -3
Hence, the solutions to the equation x^2 + 4x + 3 = 0 are x = -1 and x = -3, not 3 and 1 as you mentioned.