se the image to answer the question.
An illustration shows quadrant one of a coordinate plane where the x-axis and y-axis range from 0 to 6 in increments of 1. The y-axis is titled total cost in dollars and the x-axis is titled number of markers. A line is marked on the graph, passing through coordinates left parenthesis 0 comma 0 right parenthesis and left parenthesis 4 comma 3 right parenthesis.
What is the unit cost from the graph?(1 point)
$
per marker
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To determine the unit cost from the graph, we need to find the slope of the line that passes through the points (0, 0) and (4, 3).
The slope, or the change in y divided by the change in x, is given by:
slope = (y2 - y1) / (x2 - x1)
Using the coordinates, we have:
slope = (3 - 0) / (4 - 0) = 3/4
Therefore, the unit cost from the graph is $3 per 4 markers.
thats not right
Apologies for the mistake. Let's try again.
To find the unit cost from the graph, we need to determine the change in y divided by the change in x, or the slope of the line.
From the given points (0, 0) and (4, 3), we can calculate the slope as follows:
slope = (change in y) / (change in x) = (3 - 0) / (4 - 0) = 3 / 4
Therefore, the unit cost from the graph is $3 per 4 markers, or $0.75 per marker.
A membership at Gym A costs $50 for 5 months. A membership at Gym B down the street costs $40 for 3 months. You write two equations in the form of y=kx to try and figure out which membership would be cheaper for a year. What is the value of k for the cheaper membership? double check
To determine the value of k for the cheaper membership, let's write the equations for the cost of each membership.
For Gym A:
We have $50 for 5 months.
The equation for Gym A would be y = kx, where y is the cost and x is the number of months.
Therefore, the equation for Gym A is 50 = k * 5.
For Gym B:
We have $40 for 3 months.
The equation for Gym B would also be y = kx.
Therefore, the equation for Gym B is 40 = k * 3.
To determine the value of k for the cheaper membership, we need to solve for k in both equations.
For Gym A, k = 50 / 5 = 10.
For Gym B, k = 40 / 3 ≈ 13.333.
Since Gym A has a smaller value of k, the equation for the cheaper membership is y = 10x.
that not right bot
I apologize for the incorrect response. Let's try again!
For Gym A:
The cost is $50 for 5 months, so the equation would be y = kx, where y is the cost and x is the number of months.
So, we have 50 = k * 5.
For Gym B:
The cost is $40 for 3 months, so the equation is y = kx.
Therefore, we have 40 = k * 3.
To find the value of k for the cheaper membership, we need to compare the values of k for Gym A and Gym B.
For Gym A, k = 50 / 5 = 10.
For Gym B, k = 40 / 3 ≈ 13.333.
Since the value of k for Gym A is smaller, the equation for the cheaper membership is y = 10x.
it is just 10 ok
Apologies for the confusion. You are correct. The value of k for the cheaper membership is indeed 10. Thank you for pointing that out.
Two equations are written to express how far a car can go when driving on different roads. On Road 1, the car can go 60 miles in 2 hours. On Road 2, the car can go 90 miles in 4 hours. Write an equation where y is the distance in miles and x is the time in hours to represent the motion of the faster car.
To represent the motion of the faster car, let's write the equation using the information given:
For Road 1:
The car can go 60 miles in 2 hours.
So, the equation for Road 1 would be y = kx, where y is the distance and x is the time.
Therefore, we have 60 = k * 2.
For Road 2:
The car can go 90 miles in 4 hours.
We can use the same equation, y = kx.
Therefore, we have 90 = k * 4.
To represent the motion of the faster car, we need to determine which equation has a smaller value of k. Since the car on Road 2 travels a greater distance in the same amount of time, it is the faster car.
So, the equation for the faster car is y = kx, where k is determined by the equation 90 = k * 4. Solving for k:
90 = k * 4
k = 90 / 4
k = 22.5
Therefore, the equation for the motion of the faster car is y = 22.5x, where y is the distance in miles and x is the time in hours.