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math,correction
Can someone correct my answers thanks. Problem #1 The equation h= 16t^2+112t gives the height of an arrow, shot upward from the ground with an initial velocity of 112 ft/s, where t is the time after the arrow leaves the ground.
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How would I work this? The equation h= 16t^2 +112t gives the height of an arrow shot upward from the ground with an initial velocity of 112 ft/s, where t is the time after the arrow leaves the ground. Find the time it takes for
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The equation h=16t^2+112t gives the height of an arrow, shot upward from the ground with an initial velocity of 112ft/s,where t is the time after the arrow leaves the ground. Find the time it takes for the arrow to reach a height
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The height of an arrow shot in the air is given by the function h(t)=16t^2+144t+24, where h(t) represents the height in feet, and t represents the time in seconds. what is the maximum height of the arrow? how long does it take to
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an arrow is shot into the air with an initial velocity of 96 feet per second. the height in feet of the arrow t seconds after it was shot into the air is given by the function h(x)=16t^2+96t. find the maximum height of the arrow.
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an arrow is shot vertically upward 2 seconds later it is at a height of 42m (this may not be necesarily its highest point)with what velocity was the arrow shot, how long is the arrow in flight altogether
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An arrow is shot verticaaly upward. Two seconds later, it is at a height of 42 meters ( although this is not necessarily the highest point). with what speed was the arrow shot? how long is the arrow in flight altogether?
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an arrow is shot vertically upward 2 seconds later it is at an height of 42m (not necessarily the highest point) with what velocity was the arrow shot how long was the arrow in flight altogether
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